Smoothing out setTimeout in CoffeeScript
In short: I'd recommend that you define your own function. See solution 3.
setTimeout -> # multi-line callbacks # make the next line a little ugly , 5000
In this post, I'll quickly explore a few solutions. Note that these problems and solutions also happen with similar functions, like
Solution 1: make them one-liners
This doesn't work in all cases, but if your callback is a one-liner, the code isn't so bad:
setTimeout (-> say("hello world")), 5000
Of course, this only happens if your callback is one line. And it's not that pretty.
Solution 2: define callback variables
You can also define a callback variable, like so:
callback = -> # multi-line callbacks # are less ugly now! setTimeout(callback, 5000)
Solution 3: make a new function
One could simply define a function that does the same thing but switches the arguments.
delay = (time, fn, args...) -> setTimeout fn, time, args...
Then you can call it like this:
delay 5000, -> # multi-line callbacks aren't # ugly with a new function!
Some libraries (such as Underscore and Sugar) already define such a function, which you can use if you like how that looks. Because defining your own function is so easy, I'd recommend doing that, because it probably looks better than whatever the library supports.
As always, when passing arguments to the callback, you need a shim if you want things to work in pesky Internet Explorer.
Solution 4: mess with the existing setTimeout function
This one is a little weird and I kind of don't recommend it...but here it is anyway.
You can modify
setTimeout and allow either order of arguments. You can do
setTimeout(fn, 5000) or
setTimeout(5000, fn). Either order works. To do that, we save a reference to the "old"
setTimeout and then redefine
setTimeout. In our new
setTimeout, we swap the first and second arguments if it's in the "new" style. Check this out:
setTimeoutOld = setTimeout @setTimeout = -> if typeof arguments is 'function' # swap if we should [arguments, arguments] = [arguments, arguments] return setTimeoutOld.apply(this, arguments)
This can then be called however you like:
setTimeout -> # old method , 5000 setTimeout 5000, -> # new method
I don't love this solution because it'll confuse people who aren't familiar with your redefinition, which will likely create more problems than it'll solve. It's also worse than defining
delay in terms of both memory and speed.
I'd recommend that you make your own function and call it something like
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